x^2-10x+19=0

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Solution for x^2-10x+19=0 equation:


Simplifying
x2 + -10x + 19 = 0

Reorder the terms:
19 + -10x + x2 = 0

Solving
19 + -10x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-19' to each side of the equation.
19 + -10x + -19 + x2 = 0 + -19

Reorder the terms:
19 + -19 + -10x + x2 = 0 + -19

Combine like terms: 19 + -19 = 0
0 + -10x + x2 = 0 + -19
-10x + x2 = 0 + -19

Combine like terms: 0 + -19 = -19
-10x + x2 = -19

The x term is -10x.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10x + 25 + x2 = -19 + 25

Reorder the terms:
25 + -10x + x2 = -19 + 25

Combine like terms: -19 + 25 = 6
25 + -10x + x2 = 6

Factor a perfect square on the left side:
(x + -5)(x + -5) = 6

Calculate the square root of the right side: 2.449489743

Break this problem into two subproblems by setting 
(x + -5) equal to 2.449489743 and -2.449489743.

Subproblem 1

x + -5 = 2.449489743 Simplifying x + -5 = 2.449489743 Reorder the terms: -5 + x = 2.449489743 Solving -5 + x = 2.449489743 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + x = 2.449489743 + 5 Combine like terms: -5 + 5 = 0 0 + x = 2.449489743 + 5 x = 2.449489743 + 5 Combine like terms: 2.449489743 + 5 = 7.449489743 x = 7.449489743 Simplifying x = 7.449489743

Subproblem 2

x + -5 = -2.449489743 Simplifying x + -5 = -2.449489743 Reorder the terms: -5 + x = -2.449489743 Solving -5 + x = -2.449489743 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + x = -2.449489743 + 5 Combine like terms: -5 + 5 = 0 0 + x = -2.449489743 + 5 x = -2.449489743 + 5 Combine like terms: -2.449489743 + 5 = 2.550510257 x = 2.550510257 Simplifying x = 2.550510257

Solution

The solution to the problem is based on the solutions from the subproblems. x = {7.449489743, 2.550510257}

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